6 J of work is needed to push an object of mass 2 kg from point A to point B of the frictionless inclined plane. If the angle of inclination is 30°, the height of the plane is h, what is the length s of the inclined plane?

Answer 1

The weight is M g = 19.6 N

(Weight)* h = 6 J = work done
Solve for the elevation change, h.
That and the inclination angle will tell you the length s.

h/s = sin 30.

Get it?

Answer 2

Yes. Thank You!