Asked by devin boutte
4. What force is needed to push a 15 N object up a 20° incline at constant speed when the coefficient of friction is 0.30
Answers
Answered by
drwls
I will be happy to critique your work.
The applied force (in the direction up the incline) must equal the sum of the friction force, which is
0.3*15N*cos 20
PLUS the component of the weight DOWN the incline, which is 15N sin 20
The applied force (in the direction up the incline) must equal the sum of the friction force, which is
0.3*15N*cos 20
PLUS the component of the weight DOWN the incline, which is 15N sin 20
Answered by
devin
ok so its 15.53 n
Answered by
drwls
5.13 + 4.23 does not equal 15.53 N
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