Asked by Becky
What force do you need to push on a large crate to accelerate it at 1.8m/s2 across a rough floor? The crate has mass 32kg and the coefficient of kinetic friction between the crate and floor is 0.57
Answers
Answered by
Henry
M*g = 32kg * 9.8m/kg = 313.6 N. = Wt. of
crate. = Normal force(Fn).
Fk = u*Fn = 0.57 * 313.6 = 178.8 N. = Force of kinetic friction.
F-Fk = M*a
F-178.8 = 32 * 1.8 = 57.6
F = 57.6 + 178.8 = 236.4 N.
crate. = Normal force(Fn).
Fk = u*Fn = 0.57 * 313.6 = 178.8 N. = Force of kinetic friction.
F-Fk = M*a
F-178.8 = 32 * 1.8 = 57.6
F = 57.6 + 178.8 = 236.4 N.
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