Asked by saadia
y= tan(2tan^-1x/2), show that dy/dx= 4(1+y^2)/4+x^2
Answers
Answered by
Steve
y = tan(2arctan(x/2))
arctan(y) = 2arctan(x/2)
1/(1+y^2) y' = 4/(4+x^2)
y' = 4(1+y^2)/(4+x^2)
arctan(y) = 2arctan(x/2)
1/(1+y^2) y' = 4/(4+x^2)
y' = 4(1+y^2)/(4+x^2)
Answered by
Tasawer Shoban
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