Asked by Anonymous
lim x-0 xtan(8x)+ 2tan(8x)/(x^2+4x)
Answers
Answered by
Steve
Using L'Hopital's Rule,
lim f/g = lim f'/g'
f = (x+2) tan(8x)
g = x^2 + 4x
f' = tan(8x) + 8(x+2)sec^2(8x)
g' = 2x + 4
f'(0) = 16
g'(0) = 4
lim = 16/4 = 4
lim f/g = lim f'/g'
f = (x+2) tan(8x)
g = x^2 + 4x
f' = tan(8x) + 8(x+2)sec^2(8x)
g' = 2x + 4
f'(0) = 16
g'(0) = 4
lim = 16/4 = 4
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