Asked by azmeerahim

Given a geometric progression:
0.05, 0.2, 0.8, ... Find the sum from the 5th term to the 8th term?

Answers

Answered by Steve
That would be S8 - S4
Since r = 4

.05(4^8-1) - .05(4^4-1) = 3264
Answered by azmeerahim
a=0.05
r=4
S8=0.05(4^8-1)/3=1092.25
S4=0.05(4^4-1)/3=4.25

Sum from 5th term to 8th term is
S8-S4=1088
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