Asked by azmeerahim
Given a geometric progression:
0.05, 0.2, 0.8, ... Find the sum from the 5th term to the 8th term?
0.05, 0.2, 0.8, ... Find the sum from the 5th term to the 8th term?
Answers
Answered by
Steve
That would be S8 - S4
Since r = 4
.05(4^8-1) - .05(4^4-1) = 3264
Since r = 4
.05(4^8-1) - .05(4^4-1) = 3264
Answered by
azmeerahim
a=0.05
r=4
S8=0.05(4^8-1)/3=1092.25
S4=0.05(4^4-1)/3=4.25
Sum from 5th term to 8th term is
S8-S4=1088
r=4
S8=0.05(4^8-1)/3=1092.25
S4=0.05(4^4-1)/3=4.25
Sum from 5th term to 8th term is
S8-S4=1088
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