That would be S8 - S4
Since r = 4
.05(4^8-1) - .05(4^4-1) = 3264
Given a geometric progression:
0.05, 0.2, 0.8, ... Find the sum from the 5th term to the 8th term?
2 answers
a=0.05
r=4
S8=0.05(4^8-1)/3=1092.25
S4=0.05(4^4-1)/3=4.25
Sum from 5th term to 8th term is
S8-S4=1088
r=4
S8=0.05(4^8-1)/3=1092.25
S4=0.05(4^4-1)/3=4.25
Sum from 5th term to 8th term is
S8-S4=1088
2 answers