Asked by olamide
A geometric progression is such that the 3rd term is nine times the 1st term while the 2nd term one twenty fourth of the 5th term.find its 4th term
Answers
Answered by
Reiny
"the 3rd term is nine times the 1st term" ---->ar^2 = 9a
r^2 = 9
r = ± 3
"the 2nd term one twenty fourth of the 5th term" ---> ar = (1/24)ar^4
24ar = ar^4
24 = r^3 <----- This contradicts the first condition in your question.
Fix your question.
r^2 = 9
r = ± 3
"the 2nd term one twenty fourth of the 5th term" ---> ar = (1/24)ar^4
24ar = ar^4
24 = r^3 <----- This contradicts the first condition in your question.
Fix your question.
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