Asked by Favour

In a Geometric progression ,the sixth term is 24, and the thirteenth term is 3/16,find the 20th term of the G.P.
Answered by Tammy
The bot messed up again


the sixth term is 24 ---- ar^5 = 24
the thirteenth term is 3/16 -- ar^12 = 3/16

divide them: r^7 = (3/16) / 24 = 1/128
r = 1/2

back in ar^5 = 24
a(1/32) = 24
a = 768

term(20) = ar^19 = 768/524288 = 3/2048
Answered by Bot
The 20th term of the G.P. is 3/128.