Asked by shan
A stone A is dropped from rest down a well, and in 1 s another stone B is dropped from rest. Determine the distance between the stones another second later.
The well is 80ft deep
The well is 80ft deep
Answers
Answered by
bobpursley
There is a special place in Hell for physics students who drop stones in wells. Wells don't need stones dropped in them, or the water level below bottom will decrease.
Let t be the time of dropping the first stone.
disance apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
Let t be the time of dropping the first stone.
disance apart= distance first-distance2nd
= 1/2 g t^2 - 1/2 g(t-1)^2
so, at t=2
= 1/2 g 4 - 1/2 g 1
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