Asked by Anonymous
Stone is dropped frm rest,frm point A on a cliff,it falls 64,8m to point C,B is a point one quarter of the way down.calculate the time the stone takes to fall frm A to C.
Answers
Answered by
drwls
The time required to fall 64.8 meters, from A to C, is given by
64.8 = (g/2)*t^2 = 4.9 t^2
t = 3.64 s
You mention a point B, 1/4 of the way down, but you don't ask any question about B. The stone arrives there in half the time, 1.82 s.
64.8 = (g/2)*t^2 = 4.9 t^2
t = 3.64 s
You mention a point B, 1/4 of the way down, but you don't ask any question about B. The stone arrives there in half the time, 1.82 s.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.