Asked by Dan
The largest-caliber antiaircraft gun operated by the German air force during World War II was the 12.8 cm Flak 40. Suppose this weapon fired a 26.2 kg shell with a muzzle speed of 800 m/s. What propulsive force was necessary to attain the muzzle speed within the 6.00 m barrel? (Assume the shell moves horizontally with constant acceleration and neglect friction.)
Answers
Answered by
Damon
change in momentum = force* time
final speed = 800
final momentum = 26.2 * 800 = 20960
average speed = 400
time in barrel = 6/400
so
20960 = F (6/400)
F = 1.4*10^6 Newtons
final speed = 800
final momentum = 26.2 * 800 = 20960
average speed = 400
time in barrel = 6/400
so
20960 = F (6/400)
F = 1.4*10^6 Newtons
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.