Asked by Max
A 30-caliber rifle with a mass of 2.80 kg fires a 9.84- g bullet with a speed of 726 m/s with respect to the ground. What kinetic energy is released by the explosion of the gunpowder that fires the bullet?
Answers
Answered by
Damon
by conservation of momentum
2.8 * speed of rifle back = .00984*726
solve for speed of rifle back, Vr
Ke = (1/2)(2.8)(Vr)^2 + (1/2)(.00984)(726)^2
2.8 * speed of rifle back = .00984*726
solve for speed of rifle back, Vr
Ke = (1/2)(2.8)(Vr)^2 + (1/2)(.00984)(726)^2
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