Asked by Kelli
solve the polynomial ineqaality. express the solution set in interval notation.
x^3+x^2+64x+64>0
x^3+x^2+64x+64>0
Answers
Answered by
priyanka
332
Answered by
nina
ss33
Answered by
Reiny
x^3+x^2+64x+64>0
x^2(x+1) + 64(x+1) > 0
(x+1)(x^2 + 64) > 0
since x^2 + 64 is always positive
we just have to look at
x+1 > 0
x > -1
see
http://www.wolframalpha.com/input/?i=x%5E3%2Bx%5E2%2B64x%2B64
notice the graph is > 0 (above the x-axis) for all values of x , x >-1
The first graph looks like a straight line, but it isn't.
the scaling distorts the graph.
x^2(x+1) + 64(x+1) > 0
(x+1)(x^2 + 64) > 0
since x^2 + 64 is always positive
we just have to look at
x+1 > 0
x > -1
see
http://www.wolframalpha.com/input/?i=x%5E3%2Bx%5E2%2B64x%2B64
notice the graph is > 0 (above the x-axis) for all values of x , x >-1
The first graph looks like a straight line, but it isn't.
the scaling distorts the graph.
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