Asked by Kelli
solve the polynomial ineqaality. express the solution set in interval notation.
x^3+x^2+64x+64>0
x^3+x^2+64x+64>0
Answers
Answered by
priyanka
332
Answered by
nina
ss33
Answered by
Reiny
x^3+x^2+64x+64>0
x^2(x+1) + 64(x+1) > 0
(x+1)(x^2 + 64) > 0
since x^2 + 64 is always positive
we just have to look at
x+1 > 0
x > -1
see
http://www.wolframalpha.com/input/?i=x%5E3%2Bx%5E2%2B64x%2B64
notice the graph is > 0 (above the x-axis) for all values of x , x >-1
The first graph looks like a straight line, but it isn't.
the scaling distorts the graph.
x^2(x+1) + 64(x+1) > 0
(x+1)(x^2 + 64) > 0
since x^2 + 64 is always positive
we just have to look at
x+1 > 0
x > -1
see
http://www.wolframalpha.com/input/?i=x%5E3%2Bx%5E2%2B64x%2B64
notice the graph is > 0 (above the x-axis) for all values of x , x >-1
The first graph looks like a straight line, but it isn't.
the scaling distorts the graph.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.