Asked by Anonymous
solve by using polynomial division(16ab^3c-10ab^2c^2+12a^2b^2c/(4a^2b)
i always get 4b^2-2b+3b+-2c^3/4a^b
i always get 4b^2-2b+3b+-2c^3/4a^b
Answers
Answered by
Steve
You can only factor 2 out of the coefficients in the numerator.
Then you can only factor ab out of the variables, leaving
(8b^2c - 5bc^2 + 6abc)/2a
Then you can only factor ab out of the variables, leaving
(8b^2c - 5bc^2 + 6abc)/2a
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