Asked by justins
solve the following polynomial and rational inequalities
2x^2+x-6>0
i need some help with this
2x^2+x-6>0
i need some help with this
Answers
Answered by
Brandon
2x^2+x-6>0
A=2
B=1
C=-6
Multiply A and C together
A=2, C=-6, 2x(-6)=-12
Find factors of -12 that add up to give you a positive value of 1, B
We figure out that factors of -12 that add up to give us 1 are 4 and -3
We rewrite our equation as:
2x^2+(4x-3x)-6>0
We can group our first two and our second two and factor those.
(2x^2+4x)-(3x-6)
We factor out a 2x from first grouping
2x(x+2)
We factor out a -3 from second grouping
-3(x+2)
What is left in both groupings must be the same to complete problem
Combine our GCF's and what left as our factors
(2x-3)(x+2)>0 Solve for x on both factors.
x>(3/2) x>-2
A=2
B=1
C=-6
Multiply A and C together
A=2, C=-6, 2x(-6)=-12
Find factors of -12 that add up to give you a positive value of 1, B
We figure out that factors of -12 that add up to give us 1 are 4 and -3
We rewrite our equation as:
2x^2+(4x-3x)-6>0
We can group our first two and our second two and factor those.
(2x^2+4x)-(3x-6)
We factor out a 2x from first grouping
2x(x+2)
We factor out a -3 from second grouping
-3(x+2)
What is left in both groupings must be the same to complete problem
Combine our GCF's and what left as our factors
(2x-3)(x+2)>0 Solve for x on both factors.
x>(3/2) x>-2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.