Asked by edward
Solve the polynomial inequality and graph the solution set on a real number line. Express the solution set in interval notation
x^3+x^2+16x+16>0
What is the solution set?
(Type your answer in interval notation.)
qaz
x^3+x^2+16x+16>0
What is the solution set?
(Type your answer in interval notation.)
qaz
Answers
Answered by
Steve
it helps if you can find the roots of the function. In this case, you have
y=(x+1)(x^2+16)
So, you know the graph crosses the x-axis only at x = -1.
Since the 2nd factor is always positive, y>0 where (x+1) > 0.
Think you can take it from there?
y=(x+1)(x^2+16)
So, you know the graph crosses the x-axis only at x = -1.
Since the 2nd factor is always positive, y>0 where (x+1) > 0.
Think you can take it from there?
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