Asked by lt
Solve the polynomial inequality
x^2+5x >or= -6
(-infinity, -3]u [-2, infinity)
or [-3,-2]
x^2+5x >or= -6
(-infinity, -3]u [-2, infinity)
or [-3,-2]
Answers
Answered by
Reiny
x^2+5x >or= -6 or
x^2 + 5x + 6 ≥ 0
(x+2)(x+3) ≥ 0
the critical values are x = -2, x= -3
if we consider y = x^2 + 5x + 6 we have a parabola which opens upwards and crosses the x-axis at -2 and -3
so it will be above the x-axis (or ≥ 0 )
for
x ≤ -3 OR x ≥-2
I suppose your notation of (-infinity, -3]u [-2, infinity) means the same thing, it just looks quite awkward.
x^2 + 5x + 6 ≥ 0
(x+2)(x+3) ≥ 0
the critical values are x = -2, x= -3
if we consider y = x^2 + 5x + 6 we have a parabola which opens upwards and crosses the x-axis at -2 and -3
so it will be above the x-axis (or ≥ 0 )
for
x ≤ -3 OR x ≥-2
I suppose your notation of (-infinity, -3]u [-2, infinity) means the same thing, it just looks quite awkward.
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