Asked by Cassidy
How many grams MgCl2 will be formed from 25.6 mL of a 0.100M HCl solution reacting with excess magnesium metal
Answers
Answered by
Steve
the solution contains
.0256L * .100mol/L = .00256 mol
Mg + 2HCl = MgCl2 + H2
each 2 moles of HCl produces 1 mole of MgCl2
So, you get .00128 moles of MgCl2
or, .00128 * 59.76 = 0.076g of MgCl2
.0256L * .100mol/L = .00256 mol
Mg + 2HCl = MgCl2 + H2
each 2 moles of HCl produces 1 mole of MgCl2
So, you get .00128 moles of MgCl2
or, .00128 * 59.76 = 0.076g of MgCl2
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