Asked by James
How many grams of MgCl2 are produced when 650 mL of 3 M hydrochloric acid solution reacted with excess magnesium hydroxide solution, Mg(OH)2?
Answers
Answered by
oobleck
Mg(OH)2 + 2HCl = MgCl2 + 2H2O
0.650L * 3mol/L = 1.95 moles HCl
you get half that many moles of MgCl2
so how many grams of MgCl2 in 0.975 moles?
0.650L * 3mol/L = 1.95 moles HCl
you get half that many moles of MgCl2
so how many grams of MgCl2 in 0.975 moles?
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