Points:
left end - A, Sam - B, center of mass - C , Joe - D , right end - E
Torques about the point B:
mg•BC –F(J) •BD =0
F(J) =mg•BC/BD= 430•2.8/4.6 = 261.7(N)
Torques about the point D
F(S) •BD - mg•CD = 0
F(S)= mg•CD/BD = 430•1.8/4.6=168.2N
A uniform beam of length 7.60 m and weight 4.30 102 N is carried by two workers, Sam and Joe, as shown in the figure below.
(a) Determine the forces that each person exerts on the beam.
F_Sam = ___ N
F_Joe = ___ N
1 answer
1 answer