Asked by yoshi
                6. Prove that tan λ cos^2 λ + sin^2λ/sin λ 
= cos λ + sin λ
10. Prove that 1+tanθ/1-tanθ = sec^2θ+2tanθ/1-tan^2θ
17.Prove that sin^2w-cos^2w/tan w sin w + cos w tan w = cos w-cot w cos w
23. Find a counterexample to shows that the equation sec a – cos a = sin a sec a is not an identity.
            
            
        = cos λ + sin λ
10. Prove that 1+tanθ/1-tanθ = sec^2θ+2tanθ/1-tan^2θ
17.Prove that sin^2w-cos^2w/tan w sin w + cos w tan w = cos w-cot w cos w
23. Find a counterexample to shows that the equation sec a – cos a = sin a sec a is not an identity.
Answers
                    Answered by
            Steve
            
    PLEASE tell your classmates to use parentheses to clarify the problems!
I think you mean
(tan*cos^2 + sin^2)/sin
= (sin*cos + sin^2)/sin
= sin(cos+sin)/sin
= cos+sin
I think you mean
(1+tan)/(1-tan)
= (1+tan)^2/(1-tan^2)
= (1+2tan+tan^2)/(1-tan^2)
= (sec^2+2tan)/(1-tan^2)
I think you mean
(sin^2 - cos^2)/(tan*sin+cos*tan)
= (sin-cos)(sin+cos)/(tan(sin+cos)
= (sin-cos)/tan
= sin*cot - cos*cot
= cos-cos*cot
always try simple values for counter-examples:
a=0: 1-1 =? 0 -- yes
a=pi: -1+1 =? 0 -- yes
a=pi/4: √2 - 1/√2 =? 1/√2*√2 NO!
    
I think you mean
(tan*cos^2 + sin^2)/sin
= (sin*cos + sin^2)/sin
= sin(cos+sin)/sin
= cos+sin
I think you mean
(1+tan)/(1-tan)
= (1+tan)^2/(1-tan^2)
= (1+2tan+tan^2)/(1-tan^2)
= (sec^2+2tan)/(1-tan^2)
I think you mean
(sin^2 - cos^2)/(tan*sin+cos*tan)
= (sin-cos)(sin+cos)/(tan(sin+cos)
= (sin-cos)/tan
= sin*cot - cos*cot
= cos-cos*cot
always try simple values for counter-examples:
a=0: 1-1 =? 0 -- yes
a=pi: -1+1 =? 0 -- yes
a=pi/4: √2 - 1/√2 =? 1/√2*√2 NO!
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.