Asked by black_widow
Given that a,b,c >0
Prove : (a/b + b/c +c/a)(b/a +c/b +a/c)>0
Prove : (a/b + b/c +c/a)(b/a +c/b +a/c)>0
Answers
Answered by
bobpursley
multiply them out. just starting with term by term, one gets
1+1+1+.... and since the remaining terms are non negative, or >0, then the sum must be >0
1+1+1+.... and since the remaining terms are non negative, or >0, then the sum must be >0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.