Ask a New Question

Asked by Anya

A particle starts from the origin with a velocity of 6.0 i m/s and moves in the xy plane with a constant acceleration of (-2.0i + 4.0j)m/s^2 . at he instant the particle achieves maximum positive x-coordinate, how far is it from the origin?
12 years ago

Answers

Answered by Jose
20m
10 years ago

Related Questions

A 4.3 kg particle starts from rest and moves a distance of 3.6 m in 2.5 s under the action of a si... A particle starts from the origin with velocity 2i m/s at t = 0 and moves in the xy plane with a var... A particle starts from the origin at t = 0 with an initial velocity of 5.5 m/s along the positive x... At t=0 a particle starts from rest at x=0, y=0 and moves in the xy plane with an acceleration a=(4.0... A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the veloc... A particle starts from the origin with a velocity of 10 m/s and moves with a constant acceleration t... If an object starts at the origin (of a graph) moving to the right with a kinetic energy of 45.5 J,... When a particle starts from rests and moves with constant acceleration then why its path is always a... A particle P starts at the origin (x0,y0)=(0,0), of the plane. The particle moves in steps as follow...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use