Question

The standard free energy of activation of a reaction A is 78.2 kJ mol–1 (18.7 kcal mol–1) at 298 K. Reaction B is ten million times faster than reaction A at the same temperature. The products of each reaction are 10.0 kJ mol–1 (2.39 kcal mol–1) more stable than the reactants.

Answer 1

Is there a question here? I don't see one.

Answer 2

The questions are as follows: What is the standard free energy activation of B? What is the standard free energy activation of the reverse of reaction A? What is the standard free energy activation of the reverse of reaction B?To think two years later same exact problem, no answer. I have absolutely no idea how to calculate these things.