Asked by Tiyani
The standard free energy of a reaction At 25 oC, ∆G°= 553 J/mol for the reaction A ⟶ B+C. Determine the concentration of the substance “B” at equilibrium if only a quarter of reactant remains at equilibrium.
Group of answer choices
0.087 mol
0.349 mol
All suggested answers in this question are not close to the correct value
0.785 mol
0.262 mol
Group of answer choices
0.087 mol
0.349 mol
All suggested answers in this question are not close to the correct value
0.785 mol
0.262 mol
Answers
Answered by
DrBob222
dGo = -RTlnK
-553 = 8.314*298*ln K
ln K = -0.223
K = 0.598
The problem says 1/4 is left. How much did we start with? Is that 1/4 in moles or is it Mols/L.
-553 = 8.314*298*ln K
ln K = -0.223
K = 0.598
The problem says 1/4 is left. How much did we start with? Is that 1/4 in moles or is it Mols/L.
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