Asked by Yoo
standard free energy change of -11.70 kJ mol-1. Calculate equilibrium constant for 25 degrees C.
I got 7.772..and it's wrong
I did
-11700J/ (-2.303 x 8.314 x 298)= 2.0505277
and then e^(2.0505277)= 7.77
I don't know what I did wrong
I got 7.772..and it's wrong
I did
-11700J/ (-2.303 x 8.314 x 298)= 2.0505277
and then e^(2.0505277)= 7.77
I don't know what I did wrong
Answers
Answered by
DrBob222
One thing wrong is you used 2.303 which converts ln (base e) to log(base 10). So if you use 2.303 then you should look up 10^2.0505 and not e^2.505. (I said that wrong. Using 2.303 is ok. What isn't proper is to use the 2.303 conversion factor and not follow through with 10^2.505.
Answered by
Yoo
thank you!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.