Question
An object weighing 400.0g in air is immersed in water after being tied to a string connected to a balance. The scale now reads 364.6g.
a.) Find the loss of weight(in gram of weight) when completely submersed in water.
b.) Find the volume of the object in cm^3 and in m^3.
c.) Find the density of the object in g/cm^3 and in kg/m^3.
d.) Find the buoyant force in N on the object when it is completely submerged in water.
a.) Find the loss of weight(in gram of weight) when completely submersed in water.
b.) Find the volume of the object in cm^3 and in m^3.
c.) Find the density of the object in g/cm^3 and in kg/m^3.
d.) Find the buoyant force in N on the object when it is completely submerged in water.
Answers
a) Subtract 364.6 g from the weight in air. You get 35.4 g (weight)
b) Divide the weight loss (from a) by the weight density of water, 1.0 g/cm^3. Answer: 35.4 cm^3
c) Divide the object mass (which part (a) calls the weight) by the Volume from (b). You get 11.3 g/cm^3
d) The buoyant force in (a) is in grams weight. It equals the mass in grams. Convert to mass in kg and multiply that by g (9.8 m/s^2) for buoyant force in Newtons.
b) Divide the weight loss (from a) by the weight density of water, 1.0 g/cm^3. Answer: 35.4 cm^3
c) Divide the object mass (which part (a) calls the weight) by the Volume from (b). You get 11.3 g/cm^3
d) The buoyant force in (a) is in grams weight. It equals the mass in grams. Convert to mass in kg and multiply that by g (9.8 m/s^2) for buoyant force in Newtons.
Related Questions
Can't get correct answer
An object weighing 340 N in air is immersed in water after being tied to...
An object weighing 325 N in air is immersed in water after being tied to a string connected to a bal...
An object weighing 345 N in air is immersed in water after being tied to a string connected to a bal...
Part 2!!!!
An object weighing 305 N in air is immersed
in water after being tied to a string conne...