Asked by kia4
an object weighing 578N and suspended by two wires. each wire makes an angle of 35degree with the horizontal. find the tension on each wire.
Answers
Answered by
bobpursley
because of symettry, you can assume each wire handles half the load.
578/2=TensionLeft/sin35
solve for tension left.
because of symmetry, tensionRight has to be the same.
If the angles were different, here is the long way.
Vertical forces:
578=TensionLeft*sinLeft + TensionRight*sinRight
Horizonal forces:
TensionRight*cosRight=TensionLeft*cosLeft
so you have two equations, two unknowns, with some algebra, solvable.
578/2=TensionLeft/sin35
solve for tension left.
because of symmetry, tensionRight has to be the same.
If the angles were different, here is the long way.
Vertical forces:
578=TensionLeft*sinLeft + TensionRight*sinRight
Horizonal forces:
TensionRight*cosRight=TensionLeft*cosLeft
so you have two equations, two unknowns, with some algebra, solvable.
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