Asked by Emily
Calculate delta H for this reaction:
N2 + 3H2 --> 2NH3
I am given the bond dissociation energy for N-N (163 kJ/mol), H-H (436 kJ/mol), and N-H (391 kJ/mol)
I can't seem to find a similar problem anywhere, they are all given 2 or 3 similar equations.
N2 + 3H2 --> 2NH3
I am given the bond dissociation energy for N-N (163 kJ/mol), H-H (436 kJ/mol), and N-H (391 kJ/mol)
I can't seem to find a similar problem anywhere, they are all given 2 or 3 similar equations.
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