Calculate Delta G for each reaction using Delta Gf values: answer kJ ...thank you
a) H2(g)+I2(s)--->2HI(g)
b) MnO2(s)+2CO(g)--->Mn(s)+2CO2(g)
c) NH4Cl(s)--->NH3(g)+HCl(g)
is this correct?
a) H2(g)+I2(s)--->2HI(g)
From tables:
G HI = +1.3 kJ/mol
G H2 = 0
G I2 = 0
dG = Gprod - Greact = 2(1.3) = 2.6 kJ/mol
dG = 2.6 kJ/mol
b) MnO2(s)+2CO(g)--->Mn(s)+2CO2(g)
G MnO2 = -465.2
G CO = -137.16
G CO2 = -394.39
G MN = 0
dG = Gprod - Greact = (1(0) + 2*-394.39) - (-465.2 +2*-137.16) = -49.3
dG = -49.3 kJ/mol
c) NH4Cl(s)--->NH3(g)+HCl(g)
HCL = -95.30
NH3 = -16.4
NH4Cl = -203.89
dG = Gprod - Greact = (-203.89) - (-16.4-95.30) = -92.2 kJ/mol
dG = -92.2 kJ/mol
Thank you.
2 answers
For a the question asks for dG for the rxn so that would be 2.6 kJ and not 2.6 kJ/mol. (It's 1.3 kJ/mol and you have 2 mols of it).
a) 2.6 kJ
b)-49.3 kJ
c) 92.2 kJ
b)-49.3 kJ
c) 92.2 kJ
1 answer