Question
A gas is compressed at a constant pressure of 0.800 atm from 6.00 L to 1.00 L. In the process, 380 J of energy leaves the gas by heat.
(a) What is the work done on the gas?
(b) What is the change in its internal energy?
(a) What is the work done on the gas?
(b) What is the change in its internal energy?
Answers
Elena
W= - p•ΔV = -0.8•(-5)•10⁻³•1.013•10⁵ = =405.2 J
ΔU =Q+W=-380+405.2=252 J
ΔU =Q+W=-380+405.2=252 J
Mubarik
Student
Mubarik
1.013*10 5