W= - p•ΔV = -0.8•(-5)•10⁻³•1.013•10⁵ = =405.2 J
ΔU =Q+W=-380+405.2=252 J
A gas is compressed at a constant pressure of 0.800 atm from 6.00 L to 1.00 L. In the process, 380 J of energy leaves the gas by heat.
(a) What is the work done on the gas?
(b) What is the change in its internal energy?
3 answers
Student
1.013*10 5
1 answer