Question

Compressed air is used to fire a 41.0 g ball vertically upward from a 1.0-m-tall tube. The air exerts an upward force of 3.7 N on the ball as long as it is in the tube. How high (in m) does the ball go above the top of the tube, assuming that the acceleration due to gravity is 9.80 m/s2?

Answer 1

Set the work done on the ball by the gas equal maximum potential energy. Solve for the max. height, H.

3.7 N * 1.0 m = M*g*H

H = 3.7 J/(9.8*.041)= 9.2 m