Asked by Anonymous
If a spring is compressed 2.0 cm from its equilibrium position and the ncompressed an addition 4.0 cm, how much more work is done in the second compression than in the first?
Answers
Answered by
Larry
W = 1/2 kx^2
1st: W = 1/2 k(2^2)
2nd: W - 1/2 k(4^2)
16/4 = 4 => 4x as much
1st: W = 1/2 k(2^2)
2nd: W - 1/2 k(4^2)
16/4 = 4 => 4x as much
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