Asked by john
P: Solve each to four decimal places (x real and 0 in degrees)
5 cos x - 2 = 0, 0<orequalto x < 2pi
5 cos x - 2 = 0, 0<orequalto x < 2pi
Answers
Answered by
Steve
cosx = 2/5
x in QI or QIV
x = 21.8014°
x = 360-21.8014 = 338.1986°
If you want answers in °, you should express the domain in °, not radians.
You can easily look up special characters, so you can copy/paste θ, and not use 0.
x in QI or QIV
x = 21.8014°
x = 360-21.8014 = 338.1986°
If you want answers in °, you should express the domain in °, not radians.
You can easily look up special characters, so you can copy/paste θ, and not use 0.
Answered by
john
those are 0 in the question not θ
Answered by
Steve
oops. my bad.
Answered by
fatma zenan
x.(x+2)
Answered by
hkuku
5x+3).(x+1)=?
Answered by
Steve
(5x+3)(x+1) = 5x^2 + (5+3)x + 3
= 5x^2 + 8x + 3
Just like 53*11 = 5*10^2 + (5+3)*10 + 3 = 500+80+3 = 583
= 5x^2 + 8x + 3
Just like 53*11 = 5*10^2 + (5+3)*10 + 3 = 500+80+3 = 583
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