Asked by amar chauhan

Sulfur vapor is analyzed by photoelectron spectroscopy (PES). Measurements determine that photoelectrons associated with the 1st ionization energy of sulfur move with de Broglie wavelength λ=5.591 A˚. What is the maximum wavelength (in meters) of radiation capable of ionizing sulfur and producing this effect?
Answered by hh
What is the equation
Answered by Juan Chota Corta
Don't answer this question until monday. It is for Edx Mit midterm exam class.
Answered by b
equation please
Answered by a
did you get an answer?
Answered by chelo
How is this calculated? someone to give the little formula
Answered by c
p=h/lambda(meters) ,
E= p^2/2m + 1.659*10^-18,
LambdaMax=hc/E
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