Asked by cheri
If you analyzed each of the substances
NaBr, KOH, CrPO4, Pb(OH)2, RbCl, LiNO3
by mixing them with water in a beaker, which
substances would be most likely to fall to the
bottom of the beaker?
1. KOH and Pb(OH)2
2. CrPO4 and LiNO3
3. NaBr
4. RbCl and LiNO3
5. CrPO4 and Pb(OH)2
6. LiNO3 and NaBr
NaBr, KOH, CrPO4, Pb(OH)2, RbCl, LiNO3
by mixing them with water in a beaker, which
substances would be most likely to fall to the
bottom of the beaker?
1. KOH and Pb(OH)2
2. CrPO4 and LiNO3
3. NaBr
4. RbCl and LiNO3
5. CrPO4 and Pb(OH)2
6. LiNO3 and NaBr
Answers
Answered by
DrBob222
You need to know the solubility rules. Here is a simplified set of rules.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
Answered by
Chemstudent
CrPO4 and Pb(OH)2
All nitrates are soluble, so LiNO3 would dissolve. Sodium & potassium salts are soluble, so NaBr and KOH are out. Chlorides in this case are soluble, so RbCl is out, leaving the other two.
All nitrates are soluble, so LiNO3 would dissolve. Sodium & potassium salts are soluble, so NaBr and KOH are out. Chlorides in this case are soluble, so RbCl is out, leaving the other two.
Answered by
Anonymous
699999
Answered by
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