Asked by hi

Sulfur vapor is analyzed by photoelectron spectroscopy (PES). Measurements determine that photoelectrons associated with the 1st ionization energy of sulfur move with de Broglie wavelength λ=3.591 A˚. What is the maximum wavelength (in meters) of radiation capable of ionizing sulfur and producing this effect?

Answers

Answered by chelo
How is this calculated? someone to give the little formula
Answered by c
p=h/lambda(meters) ,
E= p^2/2m + 1.659*10^-18,
LambdaMax=hc/E
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