Asked by Gabby

Methanol is an organic solvent and is also used as fuel in some automobile engines. From the following data, calculate the standard enthalpy of formation of methanol.

2CH3OH + 3O2 --> 2CO2 + 4H2O, (delta H = -1452.8 kJ/mol
Answered by ash
(2*-393.5+4*-242)-(2*-293+0)
Delta H+ -1169 kJ/mol
Answered by DrBob222
I don't agree with the answer provided by ash.
dHxn = (n*dHf products) - 2x = -1452.
Solve for x for dHf CH3OH.
Answered by Zander
just had this question on my webassign-

products
h2o is liquid: dH= -286 kJ (x4)
CO2 (g): dH= -393.509 kJ (x2)

reactants:
CH3OH (l): dH= 2dH (unknown)
O2 (g): dH= 0 (x3) (0 bc its elemental)

dH(rxn) = dH(prod) - dH(react)
-1452.8= -1931.018 - 2dH(CH3OH)
-2dH(CH3OH) = 478.218
dH(CH3OH) = -239.109