Asked by Anonymous
The solvent for an organic reaction is prepared by mixing 50.0 of acetone () with 57.0 of ethyl acetate (). This mixture is stored at 25.0 . The vapor pressure and the densities for the two pure components at 25.0 are given in the following table. What is the vapor pressure of the stored mixture?
Answers
Answered by
DrBob222
You must have units. 50.0 what? 57.0 what? 25.0 what?
Look up the density in the table to which you refer. Use the density to convert mL to grams. Then moles = grams/molar mass.
mole fraction X = moles X/total moles.
Finally,
Pacetone = Xacetone*P<sup>o</sup><sub>acetone</sub> and
Petacetate = Xetacetate*P<sup>o</sub><sub>ethyl acetate</sub>
Then add Pacetone + Pethyl aectate.
Look up the density in the table to which you refer. Use the density to convert mL to grams. Then moles = grams/molar mass.
mole fraction X = moles X/total moles.
Finally,
Pacetone = Xacetone*P<sup>o</sup><sub>acetone</sub> and
Petacetate = Xetacetate*P<sup>o</sub><sub>ethyl acetate</sub>
Then add Pacetone + Pethyl aectate.
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