Asked by Shruti
A fishing boat leaves port at 11 miles per hour at a bearing of 210 degrees for 2 hours, then turns to a bearing of 250 degrees at 8 miles per hour for 4 hours, and finally changes to a bearing of 280 degrees at 7 miles per hour for 2 hours. At this point, the boat heads directly back to port at a speed of 8 miles per hour. Find the time it takes the boat to return to port as well as the boat's bearing as it does.
Answers
Answered by
Steve
break each section into x- and y-components. Starting at (0,0),
22 @ 210° moves (-11.00,-19.05)
32 @ 250° moves (-30.07,-10.94)
14 @ 280° moves (-13.79,2.43)
Final location: (-54.86,-27.56)
bearing to port = 63°20'
distance = 47.43
time to port = 5.93 hours
22 @ 210° moves (-11.00,-19.05)
32 @ 250° moves (-30.07,-10.94)
14 @ 280° moves (-13.79,2.43)
Final location: (-54.86,-27.56)
bearing to port = 63°20'
distance = 47.43
time to port = 5.93 hours
Answered by
Steve
distance = 61.39
time to port = 7.67 hours
time to port = 7.67 hours
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.