Question

A ship leaves port at 1:00 P.M. and sails in the direction N36°W at a rate of 25 mi/hr. Another ship leaves port at 1:30 P.M. and sails in the direction N54°E at a rate of 16 mi/hr.
(a) Approximately how far apart are the ships at 3:00 P.M.? (Round your answer to the nearest whole number.)


(b) What is the bearing, to the nearest degree, from the first ship to the second?

Answer 1

Stephanie, if you would <b>stop</b> typing in all-caps and just put "Math" in the subject line, you'd probably receive help. Anyone who shouts at tutors and demands things, usually is not helped.

Answer 2

ok, sorry, would you help me then, please

Answer 3

Did you make a diagram?
Did you realize that the angle between their paths is 90°
How easy is that ???
First ship goes for 2 hrs at 25 mph or distance = 50 miles
2nd ship goes for 1.5 hrs at 16 mph or distance = 24 miles

a) let x be the distance between them
x^2 = 50^2 + 24^2 = 3076
x = 55.46 km

Let the angle at the left of the triangle be Ø
tanØ = 24/50
Ø = appr 25.64°

Draw in horizontals and verticals at that vertex and you should be able to find the bearing between the two ships

Answer 4

ok, thanks

Answer 5

Help me for that question