Question

A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 28 mi/hr. Another ship leaves the same port at 1:30 P.M. and travels S20°W at 18 mi/hr. Approximately how far apart are the ships at 3:00 P.M.? (Round your answer to the nearest mile.)

I tried to solve it and I got 62 miles, but the answer is wrong. please HELP!
In my diagram, then angle between their path is 55°, and at 3:00 the first ship has gone 56 mi and the second ship has gone 27 miles.

Looks like a basic cosine law problem ...
x^2= 56^2 + 27^2 - 2(56)(27)cos55°
.....

x is not 62 miles, what did you get this time?

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