Asked by Olive
A fishing boat travel from a harbour on a bearing of 140 degree for 60 kilometer to an lsland a. How far due east does it travel b. Find the bearing required to return to the harbour .
Answers
Answered by
yeet my horse to the old town road
60 cos(90-140)° = 60 cos50° = 38.56 km
Actually, the bearing of the island from the harbour is 140°
The heading of the ship was thus set to 140°
Actually, the bearing of the island from the harbour is 140°
The heading of the ship was thus set to 140°
Answered by
oobleck
nice copy and paste there, yeet.
Now, why don't you answer part (b) ?
Now, why don't you answer part (b) ?
Answered by
henry2,
a. d = 60km[140o] CW from +y-axis.
X = 60*sin140 = 38.6 km.
b. 140o CW = 40o E. of S.
Return heading = 40o W. of N. = 320o CW.
So the heading is 180o greater .
X = 60*sin140 = 38.6 km.
b. 140o CW = 40o E. of S.
Return heading = 40o W. of N. = 320o CW.
So the heading is 180o greater .
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