Asked by Max
8, x, y, 24
The first three terms are geometric.
The last three terms are arithmetic.
Find x and y.
The first three terms are geometric.
The last three terms are arithmetic.
Find x and y.
Answers
Answered by
oobleck
x^2 = 8y
y-x = 24-y
solve to get
8, -8, 8, 24
or
8, 12, 18, 24
y-x = 24-y
solve to get
8, -8, 8, 24
or
8, 12, 18, 24
Answered by
mathhelper
relation #1:
x-8 = y-x
y = 2x - 8
relation #2:
y/x = 24/y
y^2 = 24x or x = y^2/24
substitution
y = 2(y^2/24) - 8
12y = y^2 - 96
y^2 - 12y - 96 = 0
solving using the formual I get
x = 7-√33, y = 6 - 3√33
or
x = 7 + √33, y = 6 + 2√33
both case work.
I was expecting some rational answers, are you sure
the question was posted corrrectly?
x-8 = y-x
y = 2x - 8
relation #2:
y/x = 24/y
y^2 = 24x or x = y^2/24
substitution
y = 2(y^2/24) - 8
12y = y^2 - 96
y^2 - 12y - 96 = 0
solving using the formual I get
x = 7-√33, y = 6 - 3√33
or
x = 7 + √33, y = 6 + 2√33
both case work.
I was expecting some rational answers, are you sure
the question was posted corrrectly?
Answered by
mathhelper
arggghhhh!
got the whole thing backwards, go with oobleck
(it was still fun doing it the wrong way)
got the whole thing backwards, go with oobleck
(it was still fun doing it the wrong way)
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