-7x^2+6x+3=0

how many real number solutions does the equation have

can you explain it by doing it...i don't get it...baby steps please

thank you

2 answers

the discriminant (b^2 - 4 a c) shows the nature of the roots (solutions)

6^2 - (4 * -7 * 3) = 36 - -84 = 120

a positive discriminant means two real roots
-7x^2+6x+3 = 0.
h = Xv = -B/2A = -6/-14 = 3/7 = .
k = Yv = -7(3/7)^2 + 6(3/7) + 3 = -9/7 + 18/7 + 21/7 = 30/7 = 4.3.
V(h, k) = V(0.43, 4.3).

For a parabola that opens downward:
k < o. No real solution.
k = 0. 1 real solution.
k > 0. 2 real solutions.