The number of real solutions to a quadratic equation can be determined by calculating the discriminant, which is given by b^2 - 4ac. If the discriminant is positive, there are two distinct real solutions. If the discriminant is zero, there is one real solution, and if the discriminant is negative, there are no real solutions.
In the given quadratic equation, the coefficients are a = 4, b = 1, and c = 3. We can calculate the discriminant as follows:
Discriminant = b^2 - 4ac = 1^2 - 4(4)(3) = 1 - 48 = -47.
Since the discriminant is negative, the quadratic equation has no real solutions.
Therefore, the correct response is:
no real solutions.
How many real solutions does the following quadratic equation have? 4x2+x+3=0 (1 point) Responses two real solutions two real solutions no real solutions no real solutions three real solutions three real solutions one real solution
1 answer
1 answer