Asked by O
How would you solve these questions using Trigonomic Identities?
sin^2x = tan^2x/1+tan^2x
sinx+cosx/tanx = 1/cosxtanx
sin^2x = tan^2x/1+tan^2x
sinx+cosx/tanx = 1/cosxtanx
Answers
Answered by
Steve
1+tan^2 = sec^2
so, the Right side is
tan^2/sec^2
= sin^2/cos^2 * cos^2
= sin^2
so, the Right side is
tan^2/sec^2
= sin^2/cos^2 * cos^2
= sin^2
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