Asked by Joyce
Please Help me solve this question
If 0.22grams of a divalent metal is deposited when a current of 0.45ampere is passed through a solution of a salt for 25 minutes. Using appropriate electrodes, calculate the relative atomic mass of the metal. (Faraday=96500)
If 0.22grams of a divalent metal is deposited when a current of 0.45ampere is passed through a solution of a salt for 25 minutes. Using appropriate electrodes, calculate the relative atomic mass of the metal. (Faraday=96500)
Answers
Answered by
DrBob222
How many Coulombs do you have? That's
C = A x seconds = 0.45 x 25 min x 60 s/min = about 675
96,500 C will deposit M/2 g of the metal where M is the atomic mass.
So M/2 x 675/96,500 = 0.22
M = ? = atomic mass of the element.
C = A x seconds = 0.45 x 25 min x 60 s/min = about 675
96,500 C will deposit M/2 g of the metal where M is the atomic mass.
So M/2 x 675/96,500 = 0.22
M = ? = atomic mass of the element.
Answered by
Akinwande Motunrayo
0.222g of a divalent metal is deposited when a current of 0.45 ampere is passed through a solution of its sought of 25mins.calculate the relative atomic mass of its metal
Answered by
maria ekere
yes
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.