Asked by Ashley
When a 0.432g sample of a mixture of volatile hydrocarbons is burned in a bomb calorimeter with heat capacity of 3046 J/C, the temperature rises by 7.82C. How much energy (in KJ) is released during combustion.
**I got that answered**
3046x7.82C=23819.72J
the answer is negative and needs to converted to Kilo Joules.
So the answer is 23.82 KJ
I need help with the second part of the question which states.
How much energy (in kJ) would be released by the combustion of 6.50g of the same mixture??
**I got that answered**
3046x7.82C=23819.72J
the answer is negative and needs to converted to Kilo Joules.
So the answer is 23.82 KJ
I need help with the second part of the question which states.
How much energy (in kJ) would be released by the combustion of 6.50g of the same mixture??
Answers
Answered by
DrBob222
23.82 kJ x (6.50g/0.432g) = ?
The above makes sense to me. Some, however, like to do these with ratio/proportion. That way is
(23.82 kJ/0.432g) = (x kJ/6.50g)
Solving for x we obtain
x kJ = 23.82 kJ x 6.50/0.432
The above makes sense to me. Some, however, like to do these with ratio/proportion. That way is
(23.82 kJ/0.432g) = (x kJ/6.50g)
Solving for x we obtain
x kJ = 23.82 kJ x 6.50/0.432
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