Question
You mix 19.5 gallons of a mixture containing 12 wt% NaCl (sol'n density = 1.0837 g/cm^3) with V2-gallon sol'n that is 20 wt% NaCl (sol'n density = 1.1453 g/cm^3). Needed mixture is 19 wt% NaCl
Whats the V2 in gallons?
(all solutions are in water so just dealing with NaCl)
Whats the V2 in gallons?
(all solutions are in water so just dealing with NaCl)
Answers
Gaurav
V1 =19.5gellon=2113.2cm^3
TM1 =2113.2*1.0837= 22900.9 g
M1= 12*TM1= 2748.1 g
V2 =?
TM2 =V2*1.1453
M2 = 20*V2*1.1453
V3=V1+V2 (mixing of two solutions)
Conservation of mass:
M3=M1+M2,
M3= 12*V1*1.0837 + 20*V2*1.1453 ....I
TM3 = TM1+TM2,
M3 = 19*TM3
= 19*(V1*1.0837 + V2*1.1453) ......II
equate equation I and II
(you have value of V1, so its just 1 variable equation)
V2= 129.158 gellons Ans
TM1 =2113.2*1.0837= 22900.9 g
M1= 12*TM1= 2748.1 g
V2 =?
TM2 =V2*1.1453
M2 = 20*V2*1.1453
V3=V1+V2 (mixing of two solutions)
Conservation of mass:
M3=M1+M2,
M3= 12*V1*1.0837 + 20*V2*1.1453 ....I
TM3 = TM1+TM2,
M3 = 19*TM3
= 19*(V1*1.0837 + V2*1.1453) ......II
equate equation I and II
(you have value of V1, so its just 1 variable equation)
V2= 129.158 gellons Ans